How much heat will water spend if it cools down from 58 degrees to 41 degrees?

univerkov | December 14, 2020 | education

given: t1 = 58 C
t2 = 41 C
c = 4200 J / kg * C
find: Q
Q = cm (t2-t1)
Q = 4200 J / kg * 1 KG * C (41 C – 58 C) = 4200 J * 1 KG * 17 C / kg * C = 71400 J = 71.4 kJ

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