How much hydrocarbon will be obtained when hydrogenating 15.6 grams of ethylene?

15.6g xg
5) C₂H₄ + H₂ → C₂H₆
28 g 30 g
ethene + hydrogen → ethane

15.6 g / 28 = x / 30;
x = 30 × 15.6 ÷ 28 = 17 g
Hence, m (C₂H₆) = 17 g
Answer: 17g



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