How much hydrochloric acid will go to the reaction with calcium carbonate if 450 g of calcium chloride is obtained?

The mass of calcium chloride is 450 g.

Let’s determine the amount of hydrochloric acid.

2HCl + CaCO3 = CaCl2 + H2O + CO2.

Let’s determine the amount of calcium chloride substance. Let’s write down the required formula.

n = m / M.

M (CaCl2) = 111.08 g / mol.

n = 450 / 111.08 = 4.05 mol.

Let’s determine the amount of hydrochloric acid according to the reaction equation.

X mol of hydrochloric acid is 4.05 mol of calcium chloride.

2 mol of hydrochloric acid – 1 mol of calcium chloride.

X = 2 * 4.05 / 1 = 8.1 mol.

Therefore, the amount of the hydrochloric acid substance is 8.1 mol.

Answer: 8.1 mol.