How much hydrogen can a 3.5 gram pentene attach?

univerkov | December 3, 2020 | education

C5H10 + H2 = C5H12
n (C5H10) = m \ M = 3.5 \ 70 = 0.05 mol
for ur-th p-i n (H2) = n (C5H10) = 0.05 mol
V (H2) = n * Vm = 0.05 * 22.4 = 1.12 l
Answer: 1.12 l

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