How much hydrogen can be displaced by sodium from 57.5 g of ethyl alcohol?

To solve, we write the equation:
2C2H5OH + 2Na = 2C2H5ONa + H2 – substitution reaction, hydrogen and sodium ethylate are released;
Let’s calculate the molar masses of substances:
M (C2H5OH) = 46 g / mol;
M (H2) = 2 g / mol.
Determine the amount of ethanol moles, if the mass is known:
Y (C2H5OH) = m / M = 57.5 / 46 = 1.25 mol.
We make the proportion according to the equation:
1.25 mol (C2H5OH) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 1.25 * 1/2 = 0.625 mol.
Find the volume of hydrogen:
V (H2) = 0.625 * 22.4 = 14 liters.
Answer: the volume of hydrogen is 14 liters.