How much hydrogen can be obtained as a result of the interaction of dilute sulfate acid with 6.22 g

How much hydrogen can be obtained as a result of the interaction of dilute sulfate acid with 6.22 g of iron, which contains 10% of impurities.

First, we write down the equation of reactions.
Fe + H2SO4 = FeSO4 + H2.
Then we calculate the mass of pure iron. We write down the following solution.
W (Fe) = W – W approx. = 100 – 10 = 90%.
6.22 g Fe is 100%.
X g Fe is 90%.
X = 6.22 × 90 ÷ 100 = 5.598 g.
Next, we find the mass of hydrogen from the reaction equation.
5.598 g Fe – x g H2.
56 g / mol Fe – 2 g / mol H2.
X = 5.598 × 2 ÷ 56 = 0.2 g H2.
Find the volume.
n = m / M.
n = V / Vm.
m / M = V / Vm.
V = m × Vm / M = 0.2 g × 22.4 l / mol ÷ 2 = 2.24 l.
This means that the volume of hydrogen is 2.24 liters.
Answer: the volume of hydrogen is 2.24 liters.



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