How much hydrogen can be obtained by decomposition of 15 kg of water at normal conditions? 2H2O = 2H2 + O2

The decomposition of water occurs in accordance with the following chemical reaction equation:

H2O = H2 + ½ O2;

Upon decomposition of 1 mole of water, 1 mole of hydrogen is synthesized.

Let’s calculate the amount of substance in 15 kilograms of water.

M H2O = 2 + 16 = 18 grams / mol;

N H2O = 15,000/18 = 833.3 mol;

The same amount of hydrogen gas will be produced.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 833.3 x 22.4 = 18 665.92 liters = 18.7 m3;