How much hydrogen can be obtained by dissolving 2.7 g of aluminum in sodium hydroxide?

To begin with, we write down the reaction equation and arrange the coefficients: 2Al + 2NaOH + 2H2O -> 2NaAlO2 + 3H2 Now we find the amount of aluminum substance 2.7 / 27 = 0.1 According to the hydrogen equation, 1.5 times more means the answer is 3.36 liters.



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