How much hydrogen can be obtained by reacting 14 g of iron with a sufficient amount of sulfuric acid?

Given:

m (Fe) = 14 g;

To find:

V (H2) -?

Decision:

1) We compose the reaction equation characteristic of the problem condition:

Fe + H2SO4 = H2 + FeSO4;

2) Find the amount of iron contained in 14 grams of metal:

n (Fe) = m: M = 14 g: 56 g / mol = 0.25 mol;

3) We compose logical equality:

if 1 mol of Fe gives 1 mol of H2,

then 0.25 mol of Fe will give x mol of H2,

then x = 0.25 mol.

4) Find the volume of hydrogen released as a result of the reaction:

V (H2) = n * Vm = 0.25 mol * 22.4 l / mol = 5.6 l.

Answer: V (H2) = 5.6 liters.