How much hydrogen can be obtained by reacting potassium with 45 g of propanol?

Let’s solve the problem, write down the equation:
2C3H7OH + 2K = 2C3H7OK + H2 – substitution reaction, hydrogen and potassium propionate are released;
Let’s calculate the molar masses of alcohol and hydrogen:
M (C3H7OH) = 60 g / mol;
M (H2) = 2 g / mol.
Determine the amount of moles of propanol by the formula:
Y (C3H7OH) = m / M = 45/60 = 0.75 mol.
Let’s make a proportion according to the equation:
0.75 mol C3H7 (OH) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.75 * 1/2 = 0.375 mol.
Find the volume of hydrogen according to Avogadro’s law:
V (H2) = 0.375 * 22.4 = 8.4 liters.
Answer: the volume of hydrogen is 8.4 liters.