How much hydrogen can be obtained by the action of 13 g of zinc per 200 g of 49%

How much hydrogen can be obtained by the action of 13 g of zinc per 200 g of 49% sulfuric acid solution? Ar (ZN) = 65, Ar (S) = 32

In sulfuric acid, zinc dissolves according to the following equation:

Zn + H2SO4 → ZnSO4 + H2;

Zinc and sulfuric acid react in the same molar amounts.

Let’s calculate the available quantities of reagents:

Let’s find the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

Let’s calculate the molar amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 200 x 0.49 / 98 = 1 mol;

The acid is taken in excess.

With this amount of zinc, it is possible to obtain 0.2 mol of hydrogen.

Let’s find the volume of hydrogen. Let’s multiply its chemical amount by the volume of 1 mole of ideal gas.

V H2 = 22.4 x 0.2 = 4.48 liters;