How much hydrogen can be obtained if aluminum weighing 16.2 g acted on hydrochloric acid?

The reaction of dissolution of aluminum in hydrochloric acid is described by the following chemical reaction equation:

Al + 3HCl = AlCl3 + 3 / 2H2;

When 1 mol of metal is dissolved, 1.5 mol of hydrogen gas is synthesized.

Let’s calculate the amount of substance contained in 16.2 grams of metal.

M Al = 27 grams / mol;

N Al = 16.2 / 27 = 0.6 mol;

When this amount of metal dissolves, 0.6 x 1.5 = 0.9 mol of hydrogen gas will be released.

Let’s calculate its volume.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V H2 = 0.9 x 22.4 = 20.16 liters;