How much hydrogen can react with 5.6 liters of butadiene?

By the condition of the problem, we write the equation:
Н2С = СН – СН = СН2 + 2Н2 = Н3С – СН2 – СН2 – СН3 – butadiene hydrogenation reaction, butane obtained;
Determine the amount of moles of butadiene by applying Avogadro’s law:
1 mol of gas at normal level – 22.4 liters;
X mol (C4H6) – 5.6 liters. hence, X mol (C4H6) = 1 * 5.6 / 22.4 = 0.25 mol.
Let’s make a proportion according to the equation:
0.25 mol (C4H6) – X mol (H2);
-1 mol                    -2 mol from here, X mol (H2) = 0.25 * 2/1 = 0.5 mol.
Let’s calculate the volume of hydrogen:
V (H2) = 0.5 * 22.4 = 11.2 liters.
Answer: the volume of hydrogen is 11.2 liters.