How much hydrogen chloride will be released when 10 liters of hydrogen reacts with chlorine?

Given: V (H2) = 10L; H2 + Cl2 = 2HCl. n – moles, V – volume.
Find: V (HCl)
n (H2) = 10 (L) / 22.4 (L / mol) = 0.45 mol
according to the reaction equation: n (HCl) = 2n (H2) = 2 × 0.45 (mol) = 0.9 (mol)
V (HCl) = 0.9 mol × 22.4 (L / mol) = 20.16 (L)
Answer: 20.16 L



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