How much hydrogen is formed by the interaction of 22.4 g of iron with an excess of hydrochloric acid.

univerkov | December 11, 2020 | education

Given:
m (Fe) = 22.4 g
HCl
Find: V (H2) -?
Decision:
Fe + 2HCl = FeCl2 + H2
n = m / M
M (Fe) = 54 g / mol
n (Fe) = 22.4 / 54 = 0.4 mol
n (Fe): n (H2) = 1: 1
n (H2) = 0.4 mol
n = V / Vm
V = m * Vm
V (H2) = 0.4 * 22.4 = 8.96 L
Answer: V (H2) = 8.96 L

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