How much hydrogen is formed by the interaction of 650 mg of zinc with an excess of hydrochloric acid.

univerkov | December 10, 2020 | education

Zn + 2HCl excess -> ZnCl2 + H2 650mg is 0.65 grams Amount of zinc substance = mass / atomic mass of zinc = 0.65 / 65 = 0.01 mol 1 mol of gas at normal conditions. takes 22.4 liters. Therefore, the volume will be 22.4 * 0.01. = 0.224 liters.

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