How much hydrogen is needed to produce 44.8 liters of water?

univerkov | December 19, 2020 | education

Given:
V (H2O) = 44.8 L
To find:
m (H2) -?
Decision.
2H2 + O2 = 2H2O
m (H2O) = 44800g
n (H2O) = m (H2O) / M (H2O) = 44800/18 = 2488.89 mol
m (H2) = 2488.89 g
Answer: 2488.89 g.

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