How much hydrogen is needed to reduce 2 mol of copper from copper (II) oxide and how much

How much hydrogen is needed to reduce 2 mol of copper from copper (II) oxide and how much water is formed in this case?

The reduction reaction of copper oxide is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

All coefficients in the equation are equal to one.

Two moles of hydrogen react with two moles of copper oxide. This produces two moles of copper and water.

Let us determine the volume of 2 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 2 x 22.4 = 44.8 liters;

Let us determine the mass of 2 mol of water.

M H2O = 2 + 16 = 18 grams / mol;

m H2O = 18 x 2 = 36 grams;