How much hydrogen is needed to reduce 6.4 g of copper from copper oxide?

The reduction reaction of copper oxide is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

One mole of hydrogen reacts with one mole of copper oxide. This produces one mole of copper.

Find the amount of substance contained in 80 grams of copper oxide.

M Cu = 64 grams / mol;

N CuO = 6.4 / 64 = 0.1 mol;

The same amount of hydrogen will react.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 0.1 x 22.4 = 2.24 liters;