The reduction reaction of copper oxide is described by the following chemical reaction equation:
CuO + H2 = Cu + H2O;
One mole of hydrogen reacts with one mole of copper oxide. This produces one mole of copper.
Find the amount of substance contained in 80 grams of copper oxide.
M Cu = 64 grams / mol;
N CuO = 6.4 / 64 = 0.1 mol;
The same amount of hydrogen will react.
One mole of ideal gas under normal conditions takes a volume of 22.4 liters.
V H2 = 0.1 x 22.4 = 2.24 liters;
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