How much hydrogen is needed to reduce glucose with 2 mol of substance to sorbitol?

Hydrogenation reaction equation:

CH2 (OH) –CH (OH) –CH (OH) –CH (OH) –CH (OH) –COH + H2 =

= CH2 (OH) –CH (OH) –CH (OH) –CH (OH) –CH (OH) – CH2OH

The solution of the problem:

n (glucose) = 2 mol, n (hydrogen) = n (glucose) = 2 mol;

V (hydrogen) = n (H2) * Vm = 2 * 22.4 = 44.8 L

Answer: 44.8 L



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