How much hydrogen is needed to reduce iron from iron (III) oxide weighing 320 kg and how much iron is formed in this case?

univerkov | February 23, 2021 | education

1.Let’s find the amount of iron (III) oxide substance – Fe2O3.

n = m: M.

M (Fe2O3) = 56 × 2 + 16 × 3 = 160 g / mol.

n = 320 g: 160 g / mol = 2 mol.

2. Let’s compose the reaction equation, find the quantitative relations of substances.

Fe2O3 + 3H2 = 2Fe + 3H2O.

For 1 mol of iron oxide, there are 3 mol of hydrogen. The substances are in quantitative ratios of 1: 3. The amount of hydrogen will be 3 times more than the amount of iron oxide.

n (Fe2O3) = 3n (H2) = 2 × 3 = 6 mol.

3. Let’s find the volume of hydrogen.

V = Vn n, where Vn is the molar volume of gas equal to 22.4 l / mol, and n is the amount of substance.

V = 6 mol × 22.4 L / mol = 134.4 L.

4. Let’s find the amount of iron substance.

For 1 mole of iron oxide, there are 2 moles of iron. The substances are in quantitative ratios of 1: 2. The amount of the iron substance will be 2 times more than the amount of the iron oxide substance.

n (Fe2O3) = 2n (Fe) = 2 × 2 = 4 mol.

Answer: V = 134.4 l; n (Fe) = 4 mol.