How much hydrogen is obtained by dissolving 27 g of aluminum in hydrochloric acid?

1. Let’s compose the equation for the reaction of aluminum with hydrochloric acid:

2Al + 6HCl = 2AlCl3 + 3H2 ↑;

2.Calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 27: 27 = 1 mol;

3. Determine the amount of released hydrogen:

n (H2) = n (Al) * 3: 2 = 1 * 3: 2 = 1.5 mol;

4. find the volume of hydrogen:

V (H2) = n (H2) * Vm = 1.5 * 22.4 = 33.6 liters.

Answer: 33.6 liters.