How much hydrogen is obtained by dissolving 27 g of aluminum in hydrochloric acid?

1. The dissolution of aluminum in hydrochloric acid occurs according to the equation:

2Al + 6HCl = 2AlCl3 + 3H2 ↑;

2.Calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 27: 27 = 1 mol;

3. Determine the amount of the resulting hydrogen:

n (H2) = 3 * n (Al): 2 = 3 * 1: 2 = 1.5 mol;

4.calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 1.5 * 22.4 = 33.6 dm3.

Answer: 33.6 dm3.