How much hydrogen is produced by the interaction of 500 g of zinc containing 20% impurities with hydrochloric acid?

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 500 x 0.8 / 65 = 6.154 mol;

The same amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 6.154 mol;

V H2 = 6.154 x 22.4 = 137.85 liters;