How much hydrogen is released if sodium weighing 69g reacts with glycerin?

We find how much hydrogen is released if sodium weighing 69g enters into a reaction with glycerin. First, we compose the reaction equations for this problem.

2 C3H5 (OH) 3 + 6 Na = 3 H2 + 2 C3H5 (ONa) 3;
Next, we find the amount of hydrogen substance.
n (H2) = 0.5 * n (Na) = 0.5 * (m (Na) / M (Na)) = 0.5 * 69 g / 23 g / mol = 1.5 mol;
Next, we find the volume of hydrogen, for this we use the following formula.
V (H2) = n (H2) × Vm;
Where V is the volume of hydrogen,
n is the amount of substance
Vm – molar volume equal to 22.4 l / mol.

V (H2) = 1.5 mol × 22.4 L / mol = 33.6 L.
Answer: V (H2) = 33.6 liters.