How much hydrogen is released when 130 g of zinc reacts with an excess of chloride acid?

Zinc reacts with hydrochloric acid. It takes twice the amount of acid to dissolve the metal.

The process is described by the following diagram:

Zn + 2HCl → ZnCl2 + H2;

The amount of hydrogen is equivalent to the amount of zinc that has entered the reaction:

Let’s calculate the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

Knowing the volume of 1 mole of gas, we determine the volume of 2 mole of hydrogen.

V H2 = 22.4 x 2 = 44.8 liters;