How much hydrogen is released when 130 grams of zinc react with dilute acid?

The interaction of zinc with any acid, for example with hydrogen chloride, occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Regardless of the type of acid, dissolving 1 mole of metal releases 1 mole of hydrogen gas.

Let’s calculate the amount of substance contained in a sample of 130 grams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 130/65 = 2 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 2 x 22.4 = 44.8 liters;