How much hydrogen is released when 327 g of 60% sulfuric acid reacts with the required amount of zinc?

Given:
m solution (H2SO4) = 327 g
ω (H2SO4) = 60%

To find:
V (H2) -?

1) H2SO4 + Zn => ZnSO4 + H2;
2) m (H2SO4) = ω * m solution / 100% = 60% * 327/100% = 196.2 g;
3) n (H2SO4) = m / M = 196.2 / 98 = 2 mol;
4) n (H2) = n (H2SO4) = 2 mol;
5) V (H2) = n * Vm = 2 * 22.4 = 44.8 liters.

Answer: The volume of H2 is 44.8 liters.