How much hydrogen is released when 600 g of 20% hydrochloric acid interacts with the required reaction?

Given:
m solution (HCl) = 600 g
ω (HCl) = 20%

To find:
V (H2) -?

1) Write the equation of a chemical reaction:
2HCl + Zn => ZnCl2 + H2 ↑;
2) Calculate the mass of HCl:
m (HCl) = ω (HCl) * m solution (HCl) / 100% = 20% * 600/100% = 120 g;
3) Calculate the amount of HCl substance:
n (HCl) = m (HCl) / M (HCl) = 120 / 36.5 = 3.29 mol;
4) Determine the amount of substance H2:
n (H2) = n (HCl) / 2 = 3.29 / 2 = 1.65 mol;
5) Calculate the volume H2:
V (H2) = n (H2) * Vm = 1.65 * 22.4 = 37 liters.

Answer: The volume of H2 is 37 liters.