How much hydrogen is required for the complete reduction of 24 g CuO?

Let’s write down the solution, make up the equation:
CuO + H2 = Cu + H2O – OBP, separation of copper and water;
We make calculations using the formulas:
M (CuO) = 79.5 g / mol;
M (H2) = 2 g / mol.
Let’s calculate the amount of copper oxide mol:
Y (CuO) = m / M = 24 / 79.5 = 0.3 mol;
Y (H2) = 0.3 mol, since according to the equation the amount of copper oxide hydrogen is equal to 1 mol.
We find the volume of hydrogen by applying Avogadro’s law:
V (H2) = 0.3 * 22.4 = 6.72 liters.
Answer: to carry out the reaction, hydrogen with a volume of 6.72 liters is required.