How much hydrogen is required for the hydrogenation of 1,3-butadiene to obtain 0.6 mol of 2-butene.

Given:
n (C4H8) = 0.6 mol
To find:
V (H2) =?
Decision:
1) Let’s compose the equation of the chemical reaction, let the volume of hydrogen be x l.
C4H6 + H2 = C4H8
2) Find the mass of butene-2
n = m / M
M (C4H8) = (12 x 4) + (1 x 8) = 56 g / mol
m = n x M
m (C4H8) = 0.6 mol x 56 g / mol = 33.6 g
3) Vm (H2) = 22.4 L / mol
4) x L: 22.4 L / mol = 33.6 g: 56 g / mol
x = (22.4 x 33.6): 56 = 13.44 liters.
Answer: V (H2) = 13.44 liters.