How much hydrogen is required for the interaction with 160 g of iron oxide (3).

univerkov | January 17, 2021 | education

Given:
m (Fe2O3) = 160 g
To find:
V (H2)
Decision:
Fe2O3 + 3H2 = 2Fe + 3H2O
n (Fe2O3) = m / M = 160 g / 160 g / mol = 1 mol
n (Fe2O3): n (H2) = 1: 3
n (H2) = 1 mol * 3 = 3 mol
V (H2) = n * Vm = 3 mol * 22.4 L / mol = 67.2 L
Answer: 67.2 l

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