How much hydrogen is required for the reaction of interaction with 24 g of copper oxide (2)?

The reduction reaction of copper oxide is described by the following chemical reaction equation.

CuO + H2 = Cu + H2O;

1 mole of metal oxide reacts with 1 mole of hydrogen. In this case, 1 mol of metal and 1 mol of water are synthesized.

Let’s calculate the chemical amount of a substance in 24 grams of metal oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 24/80 = 0.3 mol;

The same chemical amount of hydrogen will be required.

Let’s calculate its volume.

Under normal conditions, one liter of ideal gas assumes a volume of 22.4 liters.

V H2 = 0.3 x 22.4 = 6.72 liters;