How much hydrogen is required to completely hydrogenate 11.2 liters of ethylene?

Let’s implement the solution:
1. By the condition of the problem, we write:
Н2С = СН2 + Н2 = СН3 – СН3 – hydrogenation, ethane obtained;
2. Proportion:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H4) – 11.2 liters. hence, X mol (C2H4) = 1 * 11.2 / 22.4 = 0.5 mol.
Y (H2) = 0.5 mol since the amount of substances according to the equation is 1 mol.
3. Find the volume of the product:
V (H2) = 0.5 * 22.4 = 11.2 liters.
Answer: the process will require 11.2 liters of hydrogen.