How much hydrogen is required to interact with 160 g of iron oxide 3?

We find how much hydrogen (n.u.) is required to interact with 160 g of iron oxide 3. Make up the equation of reactions

Fe2O3 + 3H2 = 2Fe + 3H2O
A given mass of iron oxide.
m (Fe2O3) = 160g.
We find the amount of the substance, for this we divide the mass of iron oxide by the molar mass.
M (Fe2O3) = 160 g / mol.
M – Molar mass.
n (Fe2O3) = 160/160 = 1 mol;
Further, according to the reaction equation, we find the amount of hydrogen substance.
n (H2) = 3 mol.
Find the volume with hydrogen. To do this, we multiply the amount of substance by the normal volume.

V (H2) = 3 * 22.4 = 67.2L.
Answer: V (H2) = 67.2 liters.