How much hydrogen is required to interact with ferric iron oxide if 112 g of iron is formed?

univerkov | July 22, 2021 | education

Data: mFe is the mass of the formed iron (mFe = 112 g).

Const: Vm – molar volume (at normal conditions. Vm = 22.4 l / mol); MFe – molar mass of iron (MFe = 55.845 g / mol ≈ 56 g / mol).

1) Equation: 2Fe (iron) + 3H2O (water) = Fe2O3 (iron oxide) + 3H2 (hydrogen).

2) Amount of substance:

Iron: νFe = mFe / MFe = 112/56 = 2 mol.

Hydrogen: νH2 / νFe = 3/2 and νH2 = 3 * νFe / 2 = 3 * 2/2 = 3 mol.

3) The required volume of hydrogen: VH2 = νn2 * Vm = 3 * 22.4 = 67.2 liters.

Answer: To interact with iron oxide, 67.2 liters of hydrogen are required.

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