How much hydrogen is required to interact with iron oxide weighing 680 grams. FeO3 + H2 = Fe + H2O.

univerkov | July 27, 2021 | education

Given:
m (Fe2O3) = 680 g

To find:
V (H2) -?

1) 3H2 + Fe2O3 => 2Fe + 3H2O;
2) n (Fe2O3) = m (Fe2O3) / M (Fe2O3) = 680/160 = 4.25 mol;
3) n (H2) = n (Fe2O3) * 3 = 4.25 * 3 = 12.75 mol;
4) V (H2) = n (H2) * Vm = 12.75 * 22.4 = 285.6 liters.

Answer: The volume of H2 is 285.6 liters.

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