How much hydrogen needs to be added to Fe2O3 with a mass of 162 g for it to react completely?

According to the condition of the problem, we will compose an equation, arrange the coefficients:
Fe2O3 + 3H2 = 2Fe + 3H2O – redox reaction, iron and water are released;
Let’s calculate the molar masses of substances:
M (Fe2O3) = 159.6 g / mol;
M (H2) = 2 g / mol.
Determine the amount of moles of iron oxide, if the mass is known:
Y (Fe2O3) = m / M = 162 / 159.6 = 1.01 mol.
We make the proportion:
1.01 mol (Fe2O3) – X mol (H2);
-1 mol -3 mol from here, X mol (H2) = 1.01 * 3/1 = 3.03 mol.
Find the volume of hydrogen:
V (H2) = 3.03 * 22.4 = 67.87 liters.
Answer: the volume of hydrogen is 67.87 liters.