How much hydrogen reacts with 32 g of iron oxide (2).

1. Hydrogen reduces pure iron from its oxide by the reaction:

H2 + FeO = Fe + H2O;

2.find the amount of oxide by the formula:

n (FeO) = m (FeO): M (FeO);

M (FeO) = 56 + 16 = 72 g / mol;

n (FeO) = 32: 72 = 0.44 mol;

3.the chemical amounts of hydrogen and iron oxide (2) are related as 1: 1, that is:

n (H2) = n (FeO) = 0.44 mol;

4.Calculate the volume of consumed hydrogen in terms of the molar volume constant:

V (H2) = n (H2) * Vm = 0.44 * 22.4 = 9.86 dm3.

Answer: 9.86 dm3.