How much hydrogen reacts with 80 grams of copper oxide CuO?

The reduction reaction of copper oxide is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

One mole of hydrogen reacts with one mole of copper oxide.

Let’s find the amount of substance contained in 80 grams of copper oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 80/80 = 1 mol;

The same amount of hydrogen will react.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 1.0 x 22.4 = 22.4 liters;