How much hydrogen sulfide can be obtained by the action of hydrochloric acid on 3 mol of sodium sulfide?

Na2S + 2HCl → 2NaCl + H2S
In our case, the amount of sodium sulfide, namely Na2S = 3 mol
Then, based on the coefficients of the reaction equation n (Na2S) = n (H2S) = 3 mol
V (H2S) = Vm * n
V (H2S) = 22.4 * 3 = 67.2 (ml)



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