How much hydrogen sulphide can be burned in 800 dm3 air and how much sulfur dioxide is generated?

The volume fraction of oxygen in the air is 21%. Let’s calculate what volume of oxygen is contained in 800 dm3 of air.

V = 800 * 21/100 = 168 dm3

For convenience, let’s translate cubic decimeters into liters: 168 dm3 = 168 liters.

Hydrogen sulfide completely burns out in oxygen with the formation of sulfur dioxide and water:

2 H2S + 3 O2 = 2 H2O + 2 SO2

The amount of hydrogen sulfide substance and the amount of the substance of the formed sulfur dioxide gas will be equal. The molar volume of any gas at normal conditions is 22.4 l / mol. This means that the volumes of these gases will be equal.

The ratio of the amount of substance gases of hydrogen sulfide and oxygen is equal to 2: 3. The ratio of volumes of gases will be similar.

V (H2S) = 168 * 2/3 = 112 HP hydrogen sulfide

V (SO2) = V (H2S) = 112 HP

Answer: V (SO2) = V (H2S) = 112 liters.



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