How much hydrogen was obtained by reacting 80 g of acetic acid with potassium?

First, we write the equation
2CH3COOH + 2K = 2CH3COOK + H2
Calculating molar mass
M (CH3COOH) = 60 g / mol
m (CH3COOH) = 2 * 60 = 120 g
Vm (H2) = 22.4 l / mol
V (H2) = (80 * 22.4) /120=14.9 l
Answer: 14.9 L (H2)



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