How much hydrogen will be obtained by the interaction of hydrochloric acid weighing 7.3 grams with zinc.

The reaction of interaction of zinc with hydrogen chloride is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. In this case, 1 mol of salt is synthesized and 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of a substance in 7.3 grams of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 7.3 / 36.5 = 0.20 mol;

The same chemical amount of hydrogen will be obtained.

Let’s calculate its volume.

One liter of ideal gas under normal conditions assumes a volume of 22.4 liters

V H2 = 0.20 x 22.4 = 4.48 liters;