How much hydrogen will be released as a result of the interaction of 2.3 g of sodium

How much hydrogen will be released as a result of the interaction of 2.3 g of sodium with 188 g of a 10% phenol solution.

1. Let’s compose the equation of the proceeding reaction:

2C6H5OH + 2Na → 2C6H5ONa + H2 ↑;

2.determine the mass of phenol:

m (C6H5OH) = w (C6H5OH) * m (solution);

m (C6H5OH) = 0.1 * 188 = 18.8 g;

3.Calculate the chemical amounts of sodium and phenol:

n (Na) = m (Na): M (Na) = 2.3: 23 = 0.1 mol;

n (C6H5OH) = m (C6H5OH): M (C6H5OH);

M (C6H5OH) = 6 * 12 + 5 + 17 = 94 g / mol;

n (C6H5OH) = 18.8: 94 = 0.2 mol;

4. sodium is deficient, let’s determine the amount of hydrogen:

n (H2) = n (Na): 2 = 0.1: 2 = 0.05 mol;

5. find the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.05 * 22.4 = 1.12 dm3.

Answer: 1.12 dm3.