How much hydrogen will be released as a result of the interaction of 2.3 g of sodium with 188 g of a 10% phenol solution.
1. Let’s compose the equation of the proceeding reaction:
2C6H5OH + 2Na → 2C6H5ONa + H2 ↑;
2.determine the mass of phenol:
m (C6H5OH) = w (C6H5OH) * m (solution);
m (C6H5OH) = 0.1 * 188 = 18.8 g;
3.Calculate the chemical amounts of sodium and phenol:
n (Na) = m (Na): M (Na) = 2.3: 23 = 0.1 mol;
n (C6H5OH) = m (C6H5OH): M (C6H5OH);
M (C6H5OH) = 6 * 12 + 5 + 17 = 94 g / mol;
n (C6H5OH) = 18.8: 94 = 0.2 mol;
4. sodium is deficient, let’s determine the amount of hydrogen:
n (H2) = n (Na): 2 = 0.1: 2 = 0.05 mol;
5. find the volume of hydrogen:
V (H2) = n (H2) * Vm = 0.05 * 22.4 = 1.12 dm3.
Answer: 1.12 dm3.
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