How much hydrogen will be released during the dehydrogenation of 44.8 liters of ethane?

Let’s implement the solution:
1. We write down the equation according to the problem statement:
V = 44.8 l; X l. -?
C2H6 = H2 + C2H4 – ethane dehydrogenation, ethylene was obtained;
1 mol 1 mol.
2. Proportions:
1 mole of gas at normal level – 22.4 liters;
X mol (C2H6) – 44.8 liters. hence, X mol (C2H6) = 1 * 44.8 / 22.4 = 2 mol;
Y (H2) = 2 mol, since the amount of these substances according to the equation is 1 mol.
3. Find the volume of the product:
V (H2) = 2 * 22.4 = 44.8 liters.
Answer: in the course of the reaction, 44.8 liters of hydrogen was obtained.