How much hydrogen will be released during the interaction of sulfuric acid 96 g of magnesium?

Magnesium dissolves in sulfuric acid solution. The reaction is described by the following chemical equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s calculate the molar amount of magnesium substance.

For this purpose, we divide this weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 96/24 = 4 mol;

An equivalent amount of hydrogen gas will be obtained.

Let’s calculate the volume of hydrogen.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 4 x 22.4 = 89.6 liters;