How much hydrogen will be released from the interaction of sodium weighing 9.2 grams with water?

To solve it, we will compose an equation, select the coefficients:
2Na + 2H2O = 2NaOH + H2 – redox reaction, hydrogen and sodium hydroxide are released;
Let’s calculate the molar mass of sodium:
M (Na) = 22.9 g / mol.
Let us determine the amount of sodium moles if its mass is known:
Y (Na) = m / M = 9.2 / 22.9 = 0.4 mol.
Let’s make a proportion according to the equation:
0.4 mol (Na) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.4 * 1/2 = 0.2 mol.
Find the volume of hydrogen by applying Avogadro’s law:
V (H2) = 0.2 * 22.4 = 4.48 liters.
Answer: The volume of released hydrogen is 4.48 liters.