How much hydrogen will be released if 10.8 g of aluminum is dissolved in hydrochloric acid?

univerkov | July 24, 2021 | education

Given:
m (Al) = 10.8 g

To find:
V (H2) -?

1) 2Al + 6HCl => 2AlCl3 + 3H2 ↑;
2) n (Al) = m / M = 10.8 / 27 = 0.4 mol;
3) n (H2) = n (Al) * 3/2 = 0.4 * 3/2 = 0.6 mol;
4) V (H2) = n * Vm = 0.6 * 22.4 = 13.4 liters.

Answer: The volume of H2 is 13.44 liters.

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