How much hydrogen will be released if 97.5 grams of zinc is dissolved in chloride acid?

To obtain hydrogen using zinc, it must be placed in hydrochloric acid.

Zn + 2HCl → ZnCl2 + H2;

The amount of hydrogen will correspond to the amount of zinc taken.

Let’s calculate the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 97.5 / 65 = 1.5 mol;

Let’s calculate the volume of 1.5 mol of hydrogen.

V H2 = 22.4 x 1.5 = 33.6 liters;



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